WebJan 31, 2024 · function gradingStudents (grades) { // Write your code here for (let i = 0; i < grades.length; i++) { if ( ( (grades [i] + 2) % 5 == 0) && (grades [i] + 2 > 39)) { grades [i] = grades [i] + 2; } else if ( ( (grades [i] + 1) % 5 == 0) && (grades [i] + 2 > 39)) { grades [i] = grades [i] + 1; } } return grades; } 1 Like
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WebMySQL Solution: SELECT (CASE WHEN GRADE < 8 THEN 'NULL' ELSE NAME END) AS Name, g. Grade, s.Marks FROM Students AS s LEFT JOIN Grades AS g ON s.Marks BETWEEN g.MIN_MARK AND g.MAX_MARK ORDER BY g.Grade DESC, IF(grade >=8, Name, 'ZZZZZ'), IF(grade <8, Marks, 'NULL'); 0 Permalink kartikeraj25 8 hours ago … WebJun 11, 2024 · Hackerrank - Grading Students Solution. HackerLand University has the following grading policy: Every student receives a in the inclusive range from to . Any less than is a failing grade. Sam is a … raising the height of a dishwasher
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WebHackerrank - Grading Students Raw Grading Students.js 'use strict'; const fs = require('fs'); process.stdin.resume(); process.stdin.setEncoding('utf-8'); let inputString = ''; let currentLine = 0; process.stdin.on('data', function(inputStdin) { inputString += inputStdin; }); process.stdin.on('end', function() { WebAug 19, 2024 · Download ZIP Grading Students HackerRank Raw gradingStudents.js function gradingStudents (grades) { grades.forEach ( (grade,index) => { if (grade >= 38 && grade % 5 >= 3) { grades [index] = grade + 5 - (grade % 5) } }) return grades } Sign up for free to join this conversation on GitHub . Already have an account? Sign in to comment WebJun 6, 2024 · 1. Start processing grades of n students in a loop one by one 1.1 Let current student's grade by g. 1.2 If g is less than 38 then skip steps 1.3 to 1.4 and move to next student's grade. 1.3 Find the differerence between g and next multiple of 5 if g is greater than or equal to 38. Let the difference be d. raising the grain woodworking