WebJul 15, 2024 · s= {"one": ["two","three","four"],"two": ["five","six"],"three": ["ten","nine"],"one": ["test","succesfull"]} i need to be able to have two of the same keys with different values and still be able to access either of them independently python list dictionary Share Improve this question Follow asked Jul 15, 2024 at 5:01 user8137025 2 WebSep 24, 2010 · def all_same (items): it = iter (items) for first in it: break else: return True # empty case, note all ( []) == True return all (x == first for x in it) The above works on any iterable, not just lists, otherwise you could use: def all_same (L): return all (x == L …
python - Get key by value in dictionary - Stack Overflow
WebApr 7, 2024 · Data Structures & Algorithms in Python; Explore More Self-Paced Courses; Programming Languages. C++ Programming - Beginner to Advanced; Java Programming - Beginner to Advanced; C Programming - Beginner to Advanced; Web Development. Full Stack Development with React & Node JS(Live) Java Backend Development(Live) … WebFeb 5, 2024 · 1 I have one list of string and one dictionary. For eg: list = ["apple fell on Newton", "lemon is yellow","grass is greener"] dict = {"apple" : "fruits", "lemon" : "vegetable"} Task is to match each string from list with the key of dictionary. If it matches then return the value of the key. pitchfork png
python - Dictionary with multiple keys mapping to same value
WebMay 9, 2024 · After grouping the values, you can use max to determine the largest grouping. Example: from collections import defaultdict data = {'AGAA': 2, 'ATAA': 5, … WebBuild another dict mapping the values of the first dict to all keys that hold that value: import collections inverse_dict = collections.defaultdict (list) for key in original_dict: inverse_dict [original_dict [key]].append (key) Share Improve this answer Follow answered Jul 23, 2013 at 21:12 user2357112 253k 28 409 492 Add a comment 1 WebAug 5, 2024 · Key_1 and Key_2 have same Value_1 Key_2 and Key_3 have same Value_2. I tried this to get the common values: list_1 = [] output = [] for value in … pitchfork product designer